3.158 \(\int \frac {(b x^2+c x^4)^3}{x^2} \, dx\)

Optimal. Leaf size=43 \[ \frac {b^3 x^5}{5}+\frac {3}{7} b^2 c x^7+\frac {1}{3} b c^2 x^9+\frac {c^3 x^{11}}{11} \]

[Out]

1/5*b^3*x^5+3/7*b^2*c*x^7+1/3*b*c^2*x^9+1/11*c^3*x^11

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Rubi [A]  time = 0.02, antiderivative size = 43, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, integrand size = 17, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.118, Rules used = {1584, 270} \[ \frac {3}{7} b^2 c x^7+\frac {b^3 x^5}{5}+\frac {1}{3} b c^2 x^9+\frac {c^3 x^{11}}{11} \]

Antiderivative was successfully verified.

[In]

Int[(b*x^2 + c*x^4)^3/x^2,x]

[Out]

(b^3*x^5)/5 + (3*b^2*c*x^7)/7 + (b*c^2*x^9)/3 + (c^3*x^11)/11

Rule 270

Int[((c_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_.), x_Symbol] :> Int[ExpandIntegrand[(c*x)^m*(a + b*x^n)^p,
x], x] /; FreeQ[{a, b, c, m, n}, x] && IGtQ[p, 0]

Rule 1584

Int[(u_.)*(x_)^(m_.)*((a_.)*(x_)^(p_.) + (b_.)*(x_)^(q_.))^(n_.), x_Symbol] :> Int[u*x^(m + n*p)*(a + b*x^(q -
p))^n, x] /; FreeQ[{a, b, m, p, q}, x] && IntegerQ[n] && PosQ[q - p]

Rubi steps

\begin {align*} \int \frac {\left (b x^2+c x^4\right )^3}{x^2} \, dx &=\int x^4 \left (b+c x^2\right )^3 \, dx\\ &=\int \left (b^3 x^4+3 b^2 c x^6+3 b c^2 x^8+c^3 x^{10}\right ) \, dx\\ &=\frac {b^3 x^5}{5}+\frac {3}{7} b^2 c x^7+\frac {1}{3} b c^2 x^9+\frac {c^3 x^{11}}{11}\\ \end {align*}

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Mathematica [A]  time = 0.00, size = 43, normalized size = 1.00 \[ \frac {b^3 x^5}{5}+\frac {3}{7} b^2 c x^7+\frac {1}{3} b c^2 x^9+\frac {c^3 x^{11}}{11} \]

Antiderivative was successfully verified.

[In]

Integrate[(b*x^2 + c*x^4)^3/x^2,x]

[Out]

(b^3*x^5)/5 + (3*b^2*c*x^7)/7 + (b*c^2*x^9)/3 + (c^3*x^11)/11

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fricas [A]  time = 0.65, size = 35, normalized size = 0.81 \[ \frac {1}{11} \, c^{3} x^{11} + \frac {1}{3} \, b c^{2} x^{9} + \frac {3}{7} \, b^{2} c x^{7} + \frac {1}{5} \, b^{3} x^{5} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((c*x^4+b*x^2)^3/x^2,x, algorithm="fricas")

[Out]

1/11*c^3*x^11 + 1/3*b*c^2*x^9 + 3/7*b^2*c*x^7 + 1/5*b^3*x^5

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giac [A]  time = 0.15, size = 35, normalized size = 0.81 \[ \frac {1}{11} \, c^{3} x^{11} + \frac {1}{3} \, b c^{2} x^{9} + \frac {3}{7} \, b^{2} c x^{7} + \frac {1}{5} \, b^{3} x^{5} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((c*x^4+b*x^2)^3/x^2,x, algorithm="giac")

[Out]

1/11*c^3*x^11 + 1/3*b*c^2*x^9 + 3/7*b^2*c*x^7 + 1/5*b^3*x^5

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maple [A]  time = 0.00, size = 36, normalized size = 0.84 \[ \frac {1}{11} c^{3} x^{11}+\frac {1}{3} b \,c^{2} x^{9}+\frac {3}{7} b^{2} c \,x^{7}+\frac {1}{5} b^{3} x^{5} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((c*x^4+b*x^2)^3/x^2,x)

[Out]

1/5*b^3*x^5+3/7*b^2*c*x^7+1/3*b*c^2*x^9+1/11*c^3*x^11

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maxima [A]  time = 1.30, size = 35, normalized size = 0.81 \[ \frac {1}{11} \, c^{3} x^{11} + \frac {1}{3} \, b c^{2} x^{9} + \frac {3}{7} \, b^{2} c x^{7} + \frac {1}{5} \, b^{3} x^{5} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((c*x^4+b*x^2)^3/x^2,x, algorithm="maxima")

[Out]

1/11*c^3*x^11 + 1/3*b*c^2*x^9 + 3/7*b^2*c*x^7 + 1/5*b^3*x^5

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mupad [B]  time = 0.04, size = 35, normalized size = 0.81 \[ \frac {b^3\,x^5}{5}+\frac {3\,b^2\,c\,x^7}{7}+\frac {b\,c^2\,x^9}{3}+\frac {c^3\,x^{11}}{11} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((b*x^2 + c*x^4)^3/x^2,x)

[Out]

(b^3*x^5)/5 + (c^3*x^11)/11 + (3*b^2*c*x^7)/7 + (b*c^2*x^9)/3

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sympy [A]  time = 0.08, size = 37, normalized size = 0.86 \[ \frac {b^{3} x^{5}}{5} + \frac {3 b^{2} c x^{7}}{7} + \frac {b c^{2} x^{9}}{3} + \frac {c^{3} x^{11}}{11} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((c*x**4+b*x**2)**3/x**2,x)

[Out]

b**3*x**5/5 + 3*b**2*c*x**7/7 + b*c**2*x**9/3 + c**3*x**11/11

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